225=-16x^2+120x

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Solution for 225=-16x^2+120x equation: 



225=-16x^2+120x

We move all terms to the left:

225-(-16x^2+120x)=0

We get rid of parentheses

16x^2-120x+225=0

a = 16; b = -120; c = +225;
Δ = b2-4ac
Δ = -1202-4·16·225
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{120}{32}=3+3/4$

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